Gravitational Force Between Two Point Masses

Calculate the magnitude of Newtonian gravitational force between two point masses at a stated separation.

Key facts

What it does
Calculate the magnitude of Newtonian gravitational force between two point masses at a stated separation.
Formula
Gravitational-force magnitude F = G m1 m2 / r^2, using G = 6.67430e-11 N m^2/kg^2. This is a point-mass Newtonian model only.
You enter
First point mass · Second point mass · Separation
Worked example
Point-mass gravitational force is 8.342875e-10 N.

A clearer path to an answer

From your question to a useful result

This page keeps the calculation transparent: define the goal, enter the matching values, inspect the method, and decide what the result means in your situation.

01

Goal

Calculate the magnitude of Newtonian gravitational force between two point masses at a stated separation.

02

Inputs

First point mass · Second point mass · Separation

03

Method

Gravitational-force magnitude F = G m1 m2 / r^2, using G = 6.67430e-11 N m^2/kg^2. This is a point-mass Newtonian model only.

04

Next step

Calculate, review the assumptions below, then compare a related tool when the decision needs more context.

Gravitational Force Between Two Point Masses

Calculate the magnitude of Newtonian gravitational force between two point masses at a stated separation.

Finite nonnegative mass in kilograms.

Finite nonnegative mass in kilograms.

Finite positive center-to-center separation in metres.

Result

Enter your values above and choose Calculate to see the result here.

Calculation map

Follow the path from input to answer

Ready to calculate
01

Inputs (3)

  • First point mass Ready
  • Second point mass Ready
  • Separation Ready
02

Formula

Gravitational-force magnitude F = G m1 m2 / r^2, using G = 6.67430e-11 N m^2/kg^2. This is a point-mass Newtonian model only.

Bounded, transparent calculation

03

Result

  • Calculate to preview the result.
This diagram mirrors the calculator contract. It summarizes the declared inputs, formula, and returned outputs; it does not add a forecast or professional advice.

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Formula, assumptions, and example

Formula: Gravitational-force magnitude F = G m1 m2 / r^2, using G = 6.67430e-11 N m^2/kg^2. This is a point-mass Newtonian model only.

This calculator evaluates the inverse-square Newtonian force magnitude between two entered point masses. It uses the stated gravitational constant and does not model extended bodies, orbital behavior, or design advice.

  • Both masses are finite nonnegative point-mass values in kilograms and separation is a finite positive center-to-center distance in metres.
  • The universal gravitational constant is fixed at 6.67430e-11 N m^2/kg^2 and the force is treated as an attractive magnitude.
  • This is a point-mass Newtonian model only. Extended-body corrections, orbital prediction, structural design, and safety advice are outside scope.

Worked example: Point-mass gravitational force is 8.342875e-10 N.

Displayed input contract

  • First point mass · minimum 0 · maximum 1000000000000000
  • Second point mass · minimum 0 · maximum 1000000000000000
  • Separation · minimum 1.0E-6 · maximum 1000000000000

The displayed limits are checked before the handler runs. Model-specific domain checks may also reject impossible or non-finite inputs.

Methodology: This calculator follows the WorldCalculate input, formula, precision, and boundary policy. Read the official methodology.

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Answer-first guide

How to use the Gravitational Force Between Two Point Masses for a real question

Calculate the magnitude of Newtonian gravitational force between two point masses at a stated separation. Start with one clearly defined goal, enter values in the units shown, and keep the result attached to the assumptions below.

What this answers

This tool is useful when your question includes gravitational force, Newton gravity, point masses. It returns the outputs declared in the calculator contract rather than a live quote, approval, diagnosis, or professional sign-off.

What you enter

First point mass · Second point mass · Separation. Keep the same time period, unit system, and currency wherever the form requires comparable values.

How to check it

Run the worked example first, compare its output with the page's example, then change one input at a time. This makes an unexpected result easier to trace to a unit, boundary, or assumption.

Three checks before you rely on the answer

  1. Match the question. Confirm that the result means the quantity you need, not a similar-sounding percentage, balance, rate, or estimate.
  2. Match the inputs. Use the requested units and period, and read each hint before replacing the example values with your own.
  3. Read the boundary. Review the assumptions and limits. Both masses are finite nonnegative point-mass values in kilograms and separation is a finite positive center-to-center distance in metres.

Need a wider view? Browse Science Calculators or compare the related tools below. The WorldCalculate methodology explains how formulas, examples, limits, and revisions are reviewed.

How to use the Gravitational Force Between Two Point Masses

  1. Enter First point mass — Finite nonnegative mass in kilograms. (kg).
  2. Enter Second point mass — Finite nonnegative mass in kilograms. (kg).
  3. Enter Separation — Finite positive center-to-center separation in metres. (m).
  4. Choose Calculate and read the result panel.
  5. Use Download PDF or Download Word to save a result sheet.

Formula

Gravitational-force magnitude F = G m1 m2 / r^2, using G = 6.67430e-11 N m^2/kg^2. This is a point-mass Newtonian model only.

This calculator evaluates the inverse-square Newtonian force magnitude between two entered point masses. It uses the stated gravitational constant and does not model extended bodies, orbital behavior, or design advice.

Worked example

Point-mass gravitational force is 8.342875e-10 N.

Assumptions and limits

  • Both masses are finite nonnegative point-mass values in kilograms and separation is a finite positive center-to-center distance in metres.
  • The universal gravitational constant is fixed at 6.67430e-11 N m^2/kg^2 and the force is treated as an attractive magnitude.
  • This is a point-mass Newtonian model only. Extended-body corrections, orbital prediction, structural design, and safety advice are outside scope.

Who uses this calculator?

  • Physics students learning universal gravitation
  • Astronomy learners practicing inverse-square laws
  • Teachers checking a point-mass force example

When is it useful?

  • Calculate Newtonian force magnitude for two point masses.
  • Explore inverse-square dependence on separation.
  • Check the units and constant in a gravitation worksheet.

Context and background

The model-first approach to science

Science calculators define a system, choose an equation, apply units and constants, and show the substitution. Effects outside that model remain outside the result.

Introductory science problem solving builds from measured quantities and idealized relationships. Those models are valuable for learning and first-pass estimates, while experiments and engineering decisions need additional evidence.

Research and review

How this guide was researched

Researched by , Founder and editorial researcher at WorldCalculate.

This guide follows the live calculator's declared inputs, formula, worked example, assumptions, validation boundaries, and source-backed methodology. The review date describes editorial review of the calculator explanation; it is not a promise that external facts or rates remain current.

Read the WorldCalculate research and methodology policy

WorldCalculate visual showing scientific measurements flowing through units, an equation, substitution, result, and limits for Gravitational Force Between Two Point Masses
A scientific estimate is easier to check when measurements, units, equation, assumptions, and limits remain visible together. An original science visual connecting measured inputs, units, equations, substitution, a reproducible result, and model limits. WorldCalculate original artwork; watermark included.

Newtonian gravitation describes the attractive force between masses with an inverse-square relation. This calculator applies that relation to two ideal point masses: F = G m1 m2 / r^2. Masses are entered in kilograms, center-to-center separation in metres, and the fixed constant is 6.67430e-11 N m^2/kg^2. The result is a force magnitude in newtons. The model deliberately stops at point-mass Newtonian arithmetic. It does not correct for extended shapes, calculate an orbit, predict a trajectory, design a structure, or give safety advice. The sections below explain mass, separation, the inverse-square rule, the constant, units, examples, boundaries, validation, and why a small force result is not a complete astronomical or engineering analysis.

Small WorldCalculate visual showing measurement, units, equation, substitution, result, and limits for Gravitational Force Between Two Point Masses
The model can be reproducible while the real-world conclusion still needs context and evidence. Compact science visual showing a checked calculation without turning it into a laboratory or safety conclusion. WorldCalculate original artwork; watermark included.

The question this gravity model answers

The calculator answers one idealized question: what gravitational-force magnitude follows from two supplied masses and their separation under the Newtonian point-mass relation? The handler treats the masses as nonnegative scalar quantities, treats the separation as a positive distance, and evaluates the inverse-square formula. It does not measure a distance, identify the centers of irregular bodies, or decide whether Newtonian mechanics is accurate for a particular system.

A force magnitude is useful for checking the basic structure of universal gravitation. Larger masses increase the result directly, while larger separation reduces it through a square. The result does not identify acceleration until a mass and a net-force context are supplied, and it does not establish motion over time. The page is intentionally an equation check rather than an orbital, structural, or mission model.

  • Inputs are two masses and one separation.
  • Output is an attractive force magnitude.
  • The model is Newtonian and point-mass based.
  • Scope ends before trajectory or design analysis.

What the point-mass assumption means

A point mass is an ideal object whose mass is treated as concentrated at one location. The separation in the formula is then the distance between those two locations. This simplification is exact for the standard ideal setup and can approximate spherically symmetric bodies in appropriate external situations, but the calculator itself does not test symmetry, size, density, or location. It accepts the user-defined point-mass scenario.

For two nearby extended bodies, different parts of each body can be at different distances and the simple center-to-center expression may not capture the total interaction. Shape, orientation, rotation, and mass distribution may matter. Those effects require integration or a reviewed physical model. They are not hidden corrections in this handler, so the point-mass label must remain attached to the result.

  • Mass is concentrated at an ideal point.
  • Separation is center-to-center in this contract.
  • Body shape is not entered.
  • Extended-body corrections are outside scope.

Masses and the direct product

The two mass fields accept nonnegative values in kilograms. Each mass appears to the first power in the numerator, so doubling either mass doubles the force while the other inputs remain fixed. If both masses double, the force becomes four times as large. This direct product is a helpful check on the formula and reflects the symmetric role of the two bodies in the ideal magnitude relation.

A zero mass is allowed as a mathematical boundary and gives zero force. It does not describe an ordinary massive body, but it is useful for testing the multiplicative structure. Negative mass is rejected because this page represents ordinary mass magnitudes and the requested point-mass Newtonian model. The handler does not use a sign to encode gravitational repulsion; the modeled interaction is attractive.

  • Masses are nonnegative magnitudes.
  • Each mass scales force linearly.
  • Zero mass gives zero model force.
  • The interaction is treated as attractive.

Separation and the inverse square

Separation r is a positive distance in metres and appears squared in the denominator. Doubling separation reduces the force to one quarter, while tripling it reduces the force to one ninth. The strong distance dependence is the defining feature of the inverse-square law. A separation of zero is not allowed because the formula would divide by zero and because two distinct point locations require a positive distance in this contract.

The lower boundary is 0.000001 m and the upper boundary is 1,000,000,000,000 m. These are computational and interface limits, not a statement that the point-mass approximation is valid at both extremes. Near-zero separations can produce very large finite numbers within the contract, but the resulting number should not be interpreted as a physical collision or short-range theory.

  • Separation is strictly positive.
  • Force falls as 1/r^2.
  • Doubling distance gives one quarter force.
  • Distance bounds are not validity guarantees.

The gravitational constant

The handler uses G = 6.67430e-11 N m^2/kg^2. This constant sets the scale that connects kilogram masses and metre separation to newtons. Keeping the value explicit makes the calculation reproducible and avoids a hidden rounded constant changing a known answer. It is not an input field because this page specifies one standard Newtonian constant for every calculation.

The constant does not encode a local gravitational acceleration. Local acceleration near a planet depends on the source mass and distance and can be derived from the force-to-mass relation in a separate step. The current calculator returns the mutual force magnitude between two supplied masses. It does not substitute a surface-gravity value or infer a planet from a name.

  • G is fixed at 6.67430e-11.
  • Its unit is N m^2/kg^2.
  • G is not local surface gravity.
  • The constant is not user-editable here.

The formula and unit path

The formula is F = G m1 m2 / r^2. The units are N m^2/kg^2 multiplied by kg multiplied by kg and divided by m^2. Kilograms and metres squared cancel, leaving newtons. This dimensional path is a useful check that mass, distance, and the constant have not been mixed with a different unit system. The result is labeled N rather than left as an unqualified number.

The formula is the point-mass Newtonian boundary of the page. It does not include relativistic corrections, finite propagation, a many-body sum, a potential energy calculation, or an orbit integrator. Those models may use related quantities, but they need different inputs and questions. A short formula is not a claim that all gravitational behavior has been calculated.

  • F = G m1 m2 / r^2.
  • Unit cancellation leaves newtons.
  • The force is a magnitude.
  • No additional gravitational model is hidden.

A catalog-value example

For m1 = 5 kg, m2 = 10 kg, and r = 2 m, the numerator is G multiplied by 50 kg^2 and the denominator is 4 m^2. The result is 6.67430e-11 multiplied by 12.5, or 8.342875e-10 N. The small magnitude is expected for kilogram-scale masses at metre-scale separation because the gravitational constant is small in SI units.

This example is a calibration of the fixed constant and inverse-square operation. It does not describe a laboratory apparatus, guarantee that other forces are negligible, or show how the bodies move. A report should state that the value is the mutual point-mass gravitational force magnitude and should preserve the separation convention used in the substitution.

  • First mass: 5 kg.
  • Second mass: 10 kg.
  • Separation: 2 m.
  • Force: 8.342875e-10 N.

Zero and inclusive endpoints

Either mass may be zero and the output then becomes zero. Separation cannot be zero, but both its small positive lower endpoint and its large upper endpoint are accepted. The force remains finite across the declared range when combined with the mass bounds. These behaviors make the domain explicit and provide useful edge cases for a test suite.

An accepted endpoint is not a physical recommendation. At the small separation endpoint, treating objects as point masses may be inappropriate, and at the large endpoint, other forces or cosmological considerations could matter depending on the intended application. The handler reports only the value demanded by the bounded Newtonian formula.

  • Zero mass gives zero force.
  • Zero separation is rejected.
  • The positive separation minimum is inclusive.
  • Finite output does not prove model validity.

Force, acceleration, and weight are different

The output is mutual gravitational force. Acceleration of the first mass would require dividing the force by that mass, and acceleration of the second would use the other mass, provided the force context is defined. Weight near a body is a related force concept but normally uses a local gravitational field or acceleration. The calculator does not return either acceleration or weight and should not be relabeled as one.

A force between two masses is also only one contribution to a net force. A real object can experience contact, electromagnetic, drag, support, or other gravitational forces. The page does not sum forces or solve a motion equation. Keeping the output as N and naming both point masses prevents a basic gravitational relation from being used as an unexplained dynamics result.

  • Output is force, not acceleration.
  • Weight is not separately calculated.
  • Net force needs other interactions.
  • The result remains labeled in newtons.

Scaling and comparison checks

The formula provides several quick checks. If the first mass changes from 5 to 10 kg while the other inputs stay fixed, force doubles. If separation changes from 2 to 4 m, force becomes one quarter. If both masses double and separation doubles, the numerator grows by four and the denominator by four, leaving the force unchanged. These are mathematical checks rather than instructions for changing a physical system.

Comparisons are meaningful only when the same unit conventions and point-mass definitions are used. A radius, altitude, surface separation, and center-to-center distance are not interchangeable labels. The handler accepts one separation value and cannot infer which geometric measurement produced it. Record that definition before comparing results.

  • Mass changes are linear.
  • Distance changes are inverse-square.
  • Unit conventions must match.
  • Comparison does not supply a trajectory.

Validation and finite guards

Each mass must be a finite JavaScript number between zero and 1,000,000,000,000,000. Separation must be finite and between 0.000001 m and 1,000,000,000,000 m. Numeric strings, missing values, NaN, infinities, negative masses, zero separation, and out-of-range values are rejected. Direct handler validation prevents callers from bypassing the catalog contract.

The multiplication, division, and displayed result pass through a finite guard. The bounds keep ordinary results finite, but explicit checking preserves the output guarantee if a future contract changes. The function does not clamp a too-small distance, substitute a default, or evaluate expressions. Rejection keeps the physical scenario visible rather than silently changing it.

  • Masses must be finite nonnegative numbers.
  • Separation must be finite and positive.
  • The force result is finite-checked.
  • Invalid inputs are rejected, not clipped.

Why this is not an orbit calculator

An orbit calculation needs more than the instantaneous force magnitude. It may require initial position and velocity vectors, a reference frame, the source and test-body roles, a time integrator, and a chosen model for additional bodies or perturbations. The current page has no velocity, direction, time, or initial-state fields. It cannot determine an orbit, period, escape path, impact, or future position.

Even a two-body problem needs a defined geometry and motion state before a trajectory can be discussed. A force at one separation is one local quantity, not a time history. The catalog therefore states point-mass Newtonian model only and excludes orbital advice. Use this result as an equation term or teaching example, not as a mission or trajectory conclusion.

  • No velocity is entered.
  • No direction or time is modeled.
  • No orbit or period is calculated.
  • There is no mission-planning claim.

Why this is not structural design

The force result does not determine how a structure responds. Structural questions require geometry, supports, load paths, material properties, combinations, dynamic effects, and an acceptance criterion. A tiny or large gravitational interaction between two ideal masses does not approve a bracket, cable, building, mechanism, or attachment. The page does not calculate stress, deflection, stability, fatigue, or failure.

The same caution applies to a real installation or experiment. The input values may be hypothetical, measured, or derived, but the handler cannot tell which. It returns the formula result and no structural or safety advice. If the number enters a design, the larger analysis must supply its own reviewed assumptions and limits.

  • No load path is represented.
  • No stress or deflection is calculated.
  • No component capacity is inferred.
  • There is no structural or safety advice.

A reproducible gravity report

A clear report records both masses, defines whether separation is center-to-center, writes the value of G, and shows the inverse-square substitution. Keep the output labeled as a force magnitude in newtons and state that the modeled interaction is attractive. If the bodies are extended or the values come from a measurement, preserve that context outside the calculator rather than implying that the handler performed the correction.

End with the model boundary: point-mass Newtonian arithmetic only. This says that the result does not provide an orbit, a relativistic correction, a many-body solution, a structural assessment, or safety advice. A concise boundary makes the number easier to reuse honestly in a worksheet or a separately reviewed model.

  • Record masses and separation convention.
  • Record G and unit cancellation.
  • Label the result as attractive magnitude.
  • Attach the point-mass boundary.

Appropriate educational use

This page is useful for universal-gravitation exercises, inverse-square comparisons, dimensional analysis, and examples showing why everyday masses attract weakly. It can help learners distinguish a force relation from acceleration and trajectory equations. The zero-mass, minimum-distance, and maximum-distance cases also give clear tests for an implementation.

It should not be used as a shortcut for an orbital plan, an extended-body interaction, or a construction decision. When the question asks where an object will go, whether it will escape, or whether a structure is adequate, additional variables and review are required. Keep the calculation as one transparent point-mass result and stop there.

  • Good for inverse-square instruction.
  • Good for SI and constant checks.
  • Not an orbit or mission planner.
  • Not a structural design assessment.

Final interpretation checklist

Confirm that both masses are in kilograms, separation is a positive centre-to-centre distance in metres, and G is the stated SI constant. Check that separation is squared in the denominator and that the result is labeled N. Verify zero-mass and distance-scaling cases when reviewing the arithmetic. These steps verify the requested formula, not the adequacy of the point-mass approximation for a real pair of bodies.

Then ask whether the desired conclusion remains a Newtonian point-mass force magnitude. If it does, the output is reproducible. If it asks for an orbit, mission plan, extended-body correction, structural response, or safety decision, stop at the boundary. F = G m1 m2 / r^2 has been evaluated, and no orbital or design advice has been produced.

  • Check masses, distance, and G.
  • Check the inverse-square denominator.
  • Keep the point-mass label visible.
  • Do not extend force arithmetic into advice.

Measurement geometry and scale

The separation in this formula is a scalar distance between the modeled point locations. If measurements describe an extended object, decide whether the center-to-center approximation is justified before entering a value. A ruler reading between visible surfaces is not necessarily the distance between centers of mass. The calculator cannot add a radius correction, account for shape, or resolve an orientation. It accepts the geometric definition supplied by the user.

Mass values also need a clear boundary. A total mass, a test mass, and a distributed mass can play different roles in a larger problem even though each is expressed in kilograms. The pairwise formula is symmetric for magnitude, but acceleration or motion analysis may distinguish source and test objects. This page does not make that distinction beyond the two labels.

Writing the geometry in words before entering numbers is a simple quality check. State what each point represents, where the separation is measured, and whether the values are nominal or measured. Correct arithmetic cannot repair an unclear geometry.

  • Define point locations before measuring r.
  • Distinguish center distance from surface distance.
  • State mass roles in larger models.
  • Geometry words belong beside the numbers.

Newtonian validity and scale

The formula is classical and instantaneous in the limited textbook sense. At ordinary speeds and weak fields it provides a familiar approximation, while extreme compact objects or relativistic motion can require a different theory. The calculator does not test speed, field strength, compactness, or the applicability of a relativistic correction. Its point-mass Newtonian label is the boundary a caller must accept.

At small distances, the point-charge-like concentration of mass can also be a poor representation of a physical body. At large distances, additional masses may contribute materially to the net field. The accepted numeric range protects finite browser arithmetic but does not declare universal physical accuracy across that range.

A result should therefore be interpreted as a model output, not as a direct observation of nature. If a comparison spans very different regimes, preserve the assumptions and review whether the same Newtonian contract still applies.

  • The model is classical Newtonian gravity.
  • Relativistic corrections are absent.
  • Scale bounds do not prove applicability.
  • Regime changes need separate review.

Using one pairwise term responsibly

A larger calculation may use this force as one term in a free-body diagram, a field sum, or a teaching table. In that handoff, retain the masses, separation, constant, and point-mass assumption. If vectors are later required, attach the line direction separately because the current output contains no coordinate components.

Do not use the decimal appearance of the result as evidence that a weak force is irrelevant or that a strong force is safe. Relevance depends on the other forces, the object response, the time scale, and the question being asked. The handler does not compare gravity with any competing interaction.

The clean boundary remains point-mass Newtonian arithmetic only, with no orbital or design advice. A separately reviewed analysis may extend the result, but it must own its additional assumptions rather than attributing them to this calculator.

  • A pairwise result can be one later term.
  • Direction must be added separately.
  • Magnitude alone does not determine relevance.
  • The larger model owns its extra assumptions.

Force and gravitational potential

The force relation and gravitational potential are related but not interchangeable. The calculator returns the force magnitude at one separation. Potential energy depends on the masses and a reference convention, and changes in potential energy can be connected to work. A force value alone does not give the energy needed to move a body between two radii because that would require integrating along a path or using a separate potential relation.

This distinction is useful when a learner sees the same constant G in several equations. The current output is in newtons, not joules. It does not report a binding energy, escape speed, or orbital energy. Keeping the unit and formula attached prevents a force result from being used as an unmarked energy quantity.

The page also does not calculate acceleration. Dividing force by one of the masses can produce a two-body acceleration under a defined ideal setup, but the current handler does not perform that step. A net acceleration would require all relevant forces and a chosen reference frame.

  • The output is force, not potential energy.
  • G can appear in separate relations.
  • No path integral is performed.
  • No acceleration is returned.

Many bodies and reference frames

In a system with several massive bodies, each pair can contribute a gravitational force. The net force on a selected body is a vector sum, and the direction and location of every body matter. The current page represents only one pair and does not add a star, planet, satellite, support, or external source. Its result must not be relabeled as a many-body net force.

Motion also depends on the reference frame and initial conditions. A pairwise force at one separation is compatible with many possible velocities and trajectories. The calculator has no velocity or time field, so it cannot determine whether bodies approach, recede, orbit, collide, or remain at that separation.

This limitation is not a failure of Newton's law. It is a boundary of the selected input contract. A more complete problem needs positions, velocities, masses, and an integration or analytic method. The simple pairwise value can still be one transparent term in that analysis.

  • Only one pair is modeled.
  • Net force needs vector addition.
  • Velocity and time are absent.
  • Trajectory requires a larger state model.

Scale, uncertainty, and handoff

Because mass enters directly and separation is squared, uncertainty in separation can have a strong effect on a force estimate. A small fractional distance error can produce roughly twice that fractional effect in the inverse-square term for small perturbations. The calculator returns a point value and does not propagate measurement intervals or decide how many digits are justified.

When recording the result, identify whether masses are measured, nominal, or hypothetical and whether separation is center-to-center. Keep G and the chosen Newtonian model visible. A large number of decimal places in the output does not make the inputs or the point-mass approximation more accurate.

If the value is handed to an orbit or structure study, label it as the pairwise point-mass force term and carry its limitations forward. Do not treat the result as evidence of a trajectory, load capacity, or safe design.

  • Distance uncertainty is amplified by r^2.
  • Output precision does not create input accuracy.
  • Record measured or hypothetical status.
  • Handoff must preserve model limits.

Frequently asked questions

What is the Gravitational Force Between Two Point Masses?

Calculate the magnitude of Newtonian gravitational force between two point masses at a stated separation.

What is the formula for the Gravitational Force Between Two Point Masses?

Gravitational-force magnitude F = G m1 m2 / r^2, using G = 6.67430e-11 N m^2/kg^2. This is a point-mass Newtonian model only. This calculator evaluates the inverse-square Newtonian force magnitude between two entered point masses. It uses the stated gravitational constant and does not model extended bodies, orbital behavior, or design advice.

What do I need to use this calculator?

Enter First point mass, Second point mass, Separation, then choose Calculate.

What are the limits of this calculator?

Both masses are finite nonnegative point-mass values in kilograms and separation is a finite positive center-to-center distance in metres. The universal gravitational constant is fixed at 6.67430e-11 N m^2/kg^2 and the force is treated as an attractive magnitude. This is a point-mass Newtonian model only. Extended-body corrections, orbital prediction, structural design, and safety advice are outside scope.

Methodology

This calculator is part of the WorldCalculate library. Its formula, example, assumptions, input bounds, and output formatting follow the official methodology.

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