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Thermal Conduction Resistance Calculator — result sheet
Calculate planar thermal resistance and steady heat-transfer rate through a material slab.
Inputs used
Results
Visual chart
Breakdown
Calculation steps
Returned data table
Formula and methodology
Formula: Thermal resistance=thickness/(conductivity×area); heat rate=temperature difference/resistance.
The slab model separates geometry and material conductivity from the temperature driving difference.
This result follows the calculator's declared inputs, precision, validation boundaries, and model limits.
Input contract
- Material thickness — m; minimum 1.0E-6; maximum 1000000
- Thermal conductivity — W/(m·K); minimum 1.0E-6; maximum 1000000000
- Area — m²; minimum 1.0E-6; maximum 1000000000000
- Temperature difference — K; minimum -1000000000; maximum 1000000000
Worked example
| Input | Value |
|---|---|
| Material thickness | 0.1 |
| Thermal conductivity | 1.4 |
| Area | 2 |
| Temperature difference | 20 |
Resistance ≈0.035714 K/W; heat rate =560 W.
Assumptions and limits
- One-dimensional steady conduction uses constant conductivity and uniform area.
- Contact resistance, convection, radiation, and edge losses are not modeled.
- Temperature difference may be signed according to the chosen direction.
Calculator note
Source and methodology
Use the official WorldCalculate methodology policy for the source, formula, precision, and boundary standards behind this calculator.
Planning estimate, not financial, medical, legal, or professional advice. © WorldCalculate — reuse with attribution. Built and curated by Hassan ALRowaie.
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