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Matched Pi Attenuator — result sheet
Calculate the two equal shunt resistors and center series resistor for a symmetric matched pi attenuator.
Inputs used
Results
Visual chart
Breakdown
Calculation steps
Returned data table
Formula and methodology
Formula: K = 10^(A/20); each shunt resistor Rshunt = Z₀(K+1)/(K−1); center series resistor Rseries = Z₀(K²−1)/(2K).
A symmetric pi pad uses two equal shunt resistors and one series resistor to reduce signal voltage while matching equal source and load impedances. The result is an ideal resistive design value; it is not a component selection or high-frequency performance guarantee.
This result follows the calculator's declared inputs, precision, validation boundaries, and model limits.
Input contract
- Attenuation — dB; minimum 1.0E-6; maximum 120
- Characteristic impedance — Ω; minimum 1.0E-6; maximum 1000000
Worked example
| Input | Value |
|---|---|
| Attenuation | 10 |
| Characteristic impedance | 50 |
A 10 dB, 50 Ω matched pi attenuator uses about 96.25 Ω for each shunt resistor and 71.15 Ω for the center series resistor.
Assumptions and limits
- Source and load impedances are equal to the entered real characteristic impedance.
- The network is an ideal, symmetric, purely resistive pi attenuator with no parasitic inductance, capacitance, frequency response, or power derating modeled.
- Positive attenuation is required; verify resistor power, tolerance, layout, thermal limits, and frequency behavior before building hardware.
Calculator note
Source and methodology
Use the official WorldCalculate methodology policy for the source, formula, precision, and boundary standards behind this calculator.
Planning estimate, not financial, medical, legal, or professional advice. © WorldCalculate — reuse with attribution. Built and curated by Hassan ALRowaie.
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