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Graham's Law of Effusion Calculator — result sheet
Compare gas effusion or diffusion rates from the molar masses of two gases.
Inputs used
Results
Visual chart
Breakdown
Calculation steps
Returned data table
Formula and methodology
Formula: Rate₂/Rate₁ = √(M₁/M₂), so Rate₂ = Rate₁√(M₁/M₂).
At comparable conditions, the lighter gas has the greater ideal effusion rate because rate varies inversely with the square root of molar mass.
This result follows the calculator's declared inputs, precision, validation boundaries, and model limits.
Input contract
- Known rate of gas 1 — rate units; minimum 1.0E-6; maximum 1000000000000
- Molar mass of gas 1 — g/mol; minimum 1.0E-6; maximum 1000000
- Molar mass of gas 2 — g/mol; minimum 1.0E-6; maximum 1000000
Worked example
| Input | Value |
|---|---|
| Known rate of gas 1 | 4 |
| Molar mass of gas 1 | 4 |
| Molar mass of gas 2 | 36 |
Gas 2 rate = 1 rate unit; rate ratio = 0.25.
Assumptions and limits
- Both gases are compared under compatible temperature and pressure conditions.
- Molar mass is positive and expressed in the same mass-per-mole unit for both gases.
- The ideal Graham-law comparison does not model collisions, porous-material geometry, or bulk-flow effects.
Calculator note
Source and methodology
Use the official WorldCalculate methodology policy for the source, formula, precision, and boundary standards behind this calculator.
Planning estimate, not financial, medical, legal, or professional advice. © WorldCalculate — reuse with attribution. Built and curated by Hassan ALRowaie.
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