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Foot-Pounds of Work and Energy — result sheet
Calculate mechanical work in foot-pounds-force from a force, distance, and included angle, then convert it to joules.
Inputs used
Results
Visual chart
Breakdown
Calculation steps
Returned data table
Formula and methodology
Formula: W(ft·lbf) = F(lbf)×d(ft)×cos(angle); W(J) = W(ft·lbf)×1.355818.
A foot-pound-force is a work unit formed by moving one pound-force through one foot. The included angle matters because only the force component parallel to the displacement contributes to work. This page keeps the imperial inputs visible and also returns joules so the result can be compared with SI calculations.
This result follows the calculator's declared inputs, precision, validation boundaries, and model limits.
Input contract
- Force magnitude — lbf; minimum 0; maximum 1000000000000
- Displacement — ft; minimum 0; maximum 1000000000000
- Angle between force and motion — °; minimum 0; maximum 180
Worked example
| Input | Value |
|---|---|
| Force magnitude | 100 |
| Displacement | 5 |
| Angle between force and motion | 0 |
500 ft·lbf, or 677.909 J.
Assumptions and limits
- Force and displacement are constant over the stated path and the angle is the included angle.
- The conversion uses the NIST factor 1 ft·lbf = 1.355818 J.
- Friction, changing force, curved paths, and rotational work are not inferred from the three inputs.
Calculator note
Source and methodology
Use the official WorldCalculate methodology policy for the source, formula, precision, and boundary standards behind this calculator.
Planning estimate, not financial, medical, legal, or professional advice. © WorldCalculate — reuse with attribution. Built and curated by Hassan ALRowaie.
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