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Combustion Analysis Empirical Formula Calculator — result sheet
Estimate an empirical formula from measured masses of carbon, hydrogen, oxygen, and nitrogen in a sample.
Inputs used
Results
Visual chart
Breakdown
Calculation steps
Returned data table
Formula and methodology
Formula: Convert each elemental mass to moles, divide by the smallest positive mole amount, then multiply by the smallest integer factor that makes the ratios whole-number-like.
The page keeps the measured mass, mole amount, normalized ratio, and rounded empirical subscripts separate so rounding is visible.
This result follows the calculator's declared inputs, precision, validation boundaries, and model limits.
Input contract
- Carbon mass — g; minimum 0; maximum 1000000
- Hydrogen mass — g; minimum 0; maximum 1000000
- Oxygen mass — g; minimum 0; maximum 1000000
- Nitrogen mass — g; minimum 0; maximum 1000000
Worked example
| Input | Value |
|---|---|
| Carbon mass | 7.34 |
| Hydrogen mass | 1.85 |
| Oxygen mass | 0 |
| Nitrogen mass | 2.85 |
Normalized ratio is approximately C3.01H9.02N1, giving the empirical formula C3H9N.
Assumptions and limits
- The supplied masses represent the complete C/H/O/N composition of one sample and use grams.
- Standard atomic masses are used and normalized ratios are rounded only when a small integer factor gives a close fit.
- Molecular mass, structural isomers, impurities, measurement uncertainty, and formula validation are outside the calculation.
Calculator note
Source and methodology
Use the official WorldCalculate methodology policy for the source, formula, precision, and boundary standards behind this calculator.
Planning estimate, not financial, medical, legal, or professional advice. © WorldCalculate — reuse with attribution. Built and curated by Hassan ALRowaie.
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